博客
关于我
SSM框架中实现多文件以及单文件上传
阅读量:773 次
发布时间:2019-03-23

本文共 3375 字,大约阅读时间需要 11 分钟。

kỹ thuật员工写作风格

1. 准备工作

1.1 Trong file pom.xml thêm các phụ thuộc cần thiết

  • commons-io: commons-io: 2.5
  • commons-fileupload: commons-fileupload: 1.3.2

1.2 Trong file spring-mvc.xml thêm solverresolver:

2. Tải đầu ● khăn hai

2.1quivosrpc simplest

Langkah 1: Trong controller backend

@RequestMapping("/upload")public Object upload(HttpSession session, @RequestParam("uploadFile") MultipartFile file) {    boolean bool = false;    ServletContext context = session.getServletContext();    String realPath = context.getRealPath("/upload");    String fileName = UUID.randomUUID().toString().replace("-", "").substring(0, 15) + "_file_" + file.getOriginalFilename();    try {        file.transferTo(new File(realPath + "/" + fileName));        bool = true;    } catch (IOException e) {        e.printStackTrace();    }    return bool ? "success" : "fail";}

2.2 Frontend code

  • Form với enctype="multipart/form-data"
    -ี่ input type="file" có name attribute
  • فرض rằng sử dụng AJAX để gửi yêu cầu上传
$.ajax({    url: "/upload",    type: "POST",    data: new FormData($("#saveUploadForm")[0]),    processData: false,    contentType: false,    success: function(result) {        layer.msg(result);    },    error: function(e) {        layer.msg(e);    }});

3. Tải đầutnh Luc phổ

3.1 Backend code

private String uploadFile(String webPath, MultipartFile file, HttpSession session) {    ServletContext context = session.getServletContext();    String realPath = context.getRealPath(webPath);    String fileName = UUID.randomUUID().toString().replace("-", "").substring(0, 15) + "_file_" + file.getOriginalFilename();    try {        File file1 = new File(realPath);        if (!file1.exists()) {            file1.mkdirs();        }        file.transferTo(new File(realPath + "/" + fileName));        return webPath + "/" + fileName;    } catch (IOException e) {        e.printStackTrace();        return null;    }}

3.2 Backend controller

@RequestMapping("/upload")public Object upload(@RequestParam("file") MultipartFile[] file, HttpSession session) {    for (int i = 0; i < file.length; i++) {        MultipartFile multipartFile = file[i];        String uploadFilePath = uploadFile("/upload", multipartFile, session);        System.out.println(uploadFilePath);    }    return "success";}

3.3 Frontendcode

  • Dùng AJAX để gửi yêu cầu upload
$.ajax({    url: "/upload",    type: "POST",    data: new FormData($("#saveFileForm")[0]),    processData: false,    contentType: false,    success: function(result) {        layer.msg(result);    },    error: function(e) {        layer.msg(e);    }});

4. Upload file withprogressbar

5. Ảnh hưởng

  • ẢNH này cho thấy quá trình upload file với thanh tiến trình trong suốt
    -vatLooks good!

转载地址:http://annzk.baihongyu.com/

你可能感兴趣的文章
PC端恶意代码分析Lab1.1-5.1,从零基础到精通,收藏这篇就够了!
查看>>
PC端稳定性测试探索
查看>>
PC端编辑 但能在PC端模拟移动端预览的富文本编辑器
查看>>
PDB文件:每个开发人员都必须知道的
查看>>
springMVC学习(二)
查看>>
Pdfkit页眉和页脚
查看>>
PDF中的Pandoc语法突出显示不起作用
查看>>
pdf从结构新建书签_在PDF文件中怎样创建书签
查看>>
pdf做成翻页电子书_第一弹:常见BOOX电子书阅读器问题解答,这些技能你都会吗?...
查看>>
PDF工具箱-分割提取合并
查看>>
pdf打印骑缝章
查看>>
PDF文字识/编辑?这个工具真的很强大!
查看>>
pdf文档出现乱码如何修改
查看>>
pdf根据模板导出
查看>>
PDF调出本来存在的书签面板
查看>>
pdf转图片
查看>>
pdf转图片、提取pdf文本、提取pdf图片
查看>>
springMvc 3.0 使用基本原理
查看>>
springCloud整合RabbitMQ实现消息中间件
查看>>
pdo sqlserver
查看>>